The EX 1&3 and "(F x O) / I = D"
 

I was reading stuff at RonDexter.com (which has a bit of everything btw) and I came across this article:

Perspective and the Normal Lens

I was intrigued by this:

"We can only see the "correct" perspective of a print, movie or video if the image is viewed exactly reproduced to give the same perspective as seen by the camera. That is if the camera shoots a scene with a certain lens, it must be viewed with an enlargement the same ratio of image size to distance of viewer as it was photographed. If F=camera focal length, I=image height on film, O=image height as projected or printed, then the correct distance to be viewed is D=viewing distance.

(F x O) / I = D"

Does anyone know what "I" (image height on film) would be for the EX1&3 imagers?

I was curious if I could see the difference in an image when viewed from the "correct" distance.

Once and a while I shoot something and it will have this "depth" look (not talking about depth of field), but more like a "tilt-shift" lens effect and I wondered if focal length/viewing distance might have something to do with getting this look too. Although I think it is a result of a combination of lighting, angle, and focus, etc...

Only Sony know the exact size, there is no hard standard, but it should be close to 6.4mm wide by 4.8mm high.