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Gene Crucean
October 24th, 2006, 03:18 PM
Here is a question that will for sure get you guys thinking.

If you have a large jet plane (747) sitting on a runway that was actually a giant conveyor belt (go with it). And there is also a device on the plane that communicates with the conveyor belt to tell it how fast the plane is traveling, which would then make the conveyor belt match the speed IN REVERSE.

Can the jet take off?

Giroud Francois
October 24th, 2006, 03:29 PM
currently i am not sure if the take off speed is measured on wind speed or ground speed.
The device you described create a differential ground speed with wind speed =0 , since the plane itself is not moving at all.

Gene Crucean
October 24th, 2006, 03:32 PM
That's a good question. Ground speed.

Just to keep things simple...

If the jet was traveling at 250mph that would mean the conveyor belt would be going in 250mph in the opposite direction.

Giroud Francois
October 24th, 2006, 03:35 PM
yes, you described the same device that some people use to run indoor.
they can run as fast as they want, they are not moving.

Giroud Francois
October 24th, 2006, 03:44 PM
you can put the plane in front of a big fan and have a wind speed that allow the plane to lift vertically while not moving at all again.

Gene Crucean
October 24th, 2006, 04:02 PM
No no... no additional devices. Just givin what I said in the first post....... can the jet take off?

Giroud Francois
October 24th, 2006, 04:56 PM
if your plane roll forward on a track that runs backward at same speed, you plane is not moving. There is no chance it is taking off that way.
Actually, you have to know how the device on the plane is recording speed, since speed is recorded by unit of distance divided by unit of time.
if the reference is the surface of the conveyor belt, the speed will be different than if measured from its start position.

Emre Safak
October 24th, 2006, 06:00 PM
It would not. The wheels would be turning like mad but the plane would otherwise be still, so there would be no lift.

Dan Vance
October 24th, 2006, 06:24 PM
If, as you say, the "runway" is a conveyor belt, then we could assume that the conveyor belt is as long as a runway for a 747, so, more than 10,000 feet. As the plane's thrust increases and the belt begins to move, it will also move the air above it. Not efficiently, but when the belt is moving at high speed, it will generate quite a wind. So, I'll say, given the implausible "ifs," a lightly-loaded 747, and a conveyor capable of keeping up with it, the wind created by the moving belt could eventually let the wing produce enough lift to raise the plane off the belt. At that moment, when contact is lost with the belt, the plane would accelerate rapidly and climb away.

Greg Boston
October 24th, 2006, 06:36 PM
Actually, you have to know how the device on the plane is recording speed, since speed is recorded by unit of distance divided by unit of time.

In aircraft, you are only concerned about ground speed in determining how long it will take you to go from point A to point B. For making the aircraft fly, you must have airspeed, measured by the differential of a static source and a pitot tube which faces the oncoming wind. Airplanes fly when air moves over their wings at sufficient speed to cause lower air pressure above the wing and higher pressure on the bottom (Bernoulli's principle). The pressure difference is created by air being forced to travel a greater distance over the curved top of the wing which increases its velocity because it will try to reach the rear of the wing at the same time as the air moving below it. Air moving at a higher velocity will have lower pressure.

A fun way to demonstrate Bernoulli's principle is to take a piece of cardboard or any lightweight flat object and place it with your hand an inch or so above it. Now, take a compressed air gun and place it between your second and third fingers and blow straight down on the paper. It will lift up and stick to your hand because you are creating high velocity air traveling outward over the top of the paper.

As for the original question, it still comes down to airspeed. If the plane was facing into a headwind with sufficient velocity, the plane will fly regardless of its speed on the ground.

-gb-

Richard Alvarez
October 24th, 2006, 06:36 PM
Yes, the plane will take off.

The aircraft develops thrust by pressure WITHIN the engine. It is independent of contact with the ground.

Unlike people on a treadmill, who must push against the ground to move forward, the airplaine's thrust is generated WITHIN the engine.

It will fly.

Greg Boston
October 24th, 2006, 06:50 PM
Yes, the plane will take off.

The aircraft develops thrust by pressure WITHIN the engine. It is independent of contact with the ground.

Unlike people on a treadmill, who must push against the ground to move forward, the airplaine's thrust is generated WITHIN the engine.

It will fly.

But the thrust of the engine is used to overcome the friction of the ground and move the plane forward until sufficient airspeed is achieved for flight. If that forward inertia creates airspeed which is then fed to the conveyor to move it backwards at that speed, the wheel speed should increase, but the aircraft will not move forward.

However, if a big gust of headwind came along and got the wheels off the conveyor, the thrust of the engines would then be the sole factor and the aircraft would accelerate above the ground until it could lift off.

Just playing devil's advocate here, Richard.

-gb-

Richard Alvarez
October 24th, 2006, 06:54 PM
Planes take off from rivers all the time.

Planes take off from frozen lake beds.

The thrust from the engine, pushes the aircraft in the opposite direction THROUGH THE AIR.

What's happening beneath it is irrelevant.

Sharyn Ferrick
October 24th, 2006, 08:15 PM
A fixed wing (Non Harrier) plane takes off based on the air flow over and under the wings. Lift off speed is typically measured in terms of speed over the ground but only for convenience. This is why the plane takes off into the wind, and air craft carriers point into the wind, and power head.

If the airflow over/under the wing is not sufficient to create lift, the plane will not take off

Sharyn
Having flown turbo prop/jet aircraft for years ;-)

Sharyn Ferrick
October 24th, 2006, 08:21 PM
A jet flying at mach 3 crosses over laser tower on the ground. At the same precise moment a laser beam is flashed from the Jet and the tower on a target the same distance ahead. Which laser beam hits the target first ?

Sharyn

Greg Boston
October 24th, 2006, 08:34 PM
What's happening beneath it is irrelevant.

Have to disagree Richard (respectfully of course). Say my aircraft is sitting in a muddy field and the tires are sinking in. I put the throttle to the wall. The excess ground friction will not allow the aircraft to move forward and it will never get off the ground.

Or, I pull into position on the runway and stand on the brakes while going to full throttle. The aircraft will just sit there as the engine produces full thrust. This is in fact the procedure for short-field take-off.

What's happening beneath an aircraft in contact with the earth is indeed relevant.

The question here is does the counter movement of the conveyor belt create the effect of zero forward movement upon the surface of the earth, like being stuck in the mud.

-gb-

Greg Boston
October 24th, 2006, 08:44 PM
Lift off speed is typically measured in terms of speed over the ground but only for convenience.

But it's always the airspeed indicator you reference, correct? (It has been for me). If you have a 30kt headwind, you take-off roll is over the ground at 30kts less than your airspeed indicator. But as we know, the airplane only cares how fast the air moves over its wings.

-gb-

Richard Alvarez
October 24th, 2006, 08:56 PM
Greg.

Irrelevant was a poor choice of words.

We have determined that the mud and brakes PREVENT THE WHEELS FROM TURNING.

The conveyor belt will do no such thing. There is no more friction than when the plane is rolling along at any speed. The engines have the power to move the plane through the air, while the wheels are rolling along the ground.

The 'ground speed' indicator of the wheels on such a takeoff would indicate a nominal double of airspeed, assuming still air.

Mike Teutsch
October 24th, 2006, 08:59 PM
A jet flying at mach 3 crosses over laser tower on the ground. At the same precise moment a laser beam is flashed from the Jet and the tower on a target the same distance ahead. Which laser beam hits the target first ?

Sharyn


They both hit at the same time, as the speed of light is always the same, which I think is 186,000 miles/sec.

Use a bullet and you have a different story though!

Mike

Greg Boston
October 24th, 2006, 09:05 PM
Greg.

Irrelevant was a poor choice of words.

We have determined that the mud and brakes PREVENT THE WHEELS FROM TURNING.

The conveyor belt will do no such thing. There is no more friction than when the plane is rolling along at any speed. The engines have the power to move the plane through the air, while the wheels are rolling along the ground.

I wish I still had my RC planes. I'd throw one on a treadmill and try it. And of course I would videotape it all for the amusement of everyone here. (-:

I just like to throw out the various thought processes to have a good discussion so don't take me too seriously on this.

-gb-

Mike Teutsch
October 24th, 2006, 09:08 PM
As far as the plane question______

It indeed would take off and fly and here is why.

The conveyor sensing or communicating device you said is measuring "how fast the plane is moving" not how fast the wheels are turning, so if the plane doesn't move the belt doesn't move.

Obviously the plane will move when the thrust is applied and when the belt moves all it will do is change the speed at which the aircrafts wheels are turning.

I'm assumming that you mean that the conveyor belt is moving forward to match the planes speed, so all that would happen is the the plane would take off without the wheels ever making a single rotation. If the belt is going in the other direction, the wheels would simply turn twice as fast until lift off, if the Goodyears hold up! :)

It would save a bunch of tire wear if they go in the same direction!

Mike

Richard Alvarez
October 24th, 2006, 09:18 PM
All in good fun Greg. I'm crunching renders, hence my terse replies.

Basically, the thrust from the engines is generated against the wings, transmitted into forward motion. It is incorrect, but often stated, that the thrust from the engines pushes 'against the air'... but for our purposes, that's close enough. The hot air is expelled, pushing the airplane forward. The wheels beneath the plane are there to ease the friction against the ground. They are still free to roll in this example. Hence, the thrust moves the plane forward, the wheels rotate twice as fast, and the plane gets enough airspeed to lift off.

A closer analogy, but still flawed, would be to imagine your person on a treadmill, wearing rollerskates. He holds in his hands, a rope connected to the far wall. The faster he pulls himself forward, the faster the treadmill rotates beneath him. BUT HIS PROPULSION comes from the interaction of his hands and the rope, not the wheels.

Make sense?

Greg Boston
October 25th, 2006, 07:01 AM
A closer analogy, but still flawed, would be to imagine your person on a treadmill, wearing rollerskates. He holds in his hands, a rope connected to the far wall. The faster he pulls himself forward, the faster the treadmill rotates beneath him. BUT HIS PROPULSION comes from the interaction of his hands and the rope, not the wheels.

That would also make for a funny video. (hehe)

The demonstration of Bernoulli's principle I outlined in an earlier post always baffles the uneducated. They just can't believe you can lift something up by blowing DOWN on it.

-gb-

Gene Crucean
October 25th, 2006, 09:01 AM
Nice call Richard. He nailed it from the get go... and with really good examples.

You guys wouldn't believe me if I told you how crazy convorsations get with this question. On another forum I saw one guy who claimed to be an engineer and refused to believe it would take off. That thread was like 20 pages long at least.

And for the record, in my experience probably 95% of people get this question wrong. It just feels so wrong to answer correctly. :)

Richard Alvarez
October 25th, 2006, 09:11 AM
I'm just curious... how many pilots answered incorrectly?

Gene Crucean
October 25th, 2006, 10:59 AM
I'm not sure any pilots were on the forum I referred to. It was a motocross website.

I'll try and dig up the thread. It's worth a read just based on the fact that it will make people not be so hard headed when they are 'positive' they are right. :)

I got this question correct initially but once I thought about it I thought my answer was way to simple. So I second guessed myself thinking there was actually something more to it. So my official answer was wrong :) Next time I'm gonna stick to my instinct.

Cole McDonald
October 25th, 2006, 11:16 AM
yes, the plane could take off as it doesn't exert force against the ground to gain momentum...making the treadmill irrelevant.

Chris Barcellos
October 25th, 2006, 11:59 AM
A jet flying at mach 3 crosses over laser tower on the ground. At the same precise moment a laser beam is flashed from the Jet and the tower on a target the same distance ahead. Which laser beam hits the target first ?

Sharyn

Not mensa but:

Plane: Unless conveyor belt is creating airspeed to flow across the wing, it will not fly. What is happening in the scenario provided is that the thrust from the engines trying to get plane up to airs speed, is being offset by an equal counter force, offsetting it.


Laser question: They tie. The speed of light is a constant. Laser is at light speed. Light wave emitted from a single point in time and space will reach a distant object at the same time. Now there may be some red shift, which would allow measurement of relative speeds of the sources, but both beams should arrive at same time.

Chris Barcellos
October 25th, 2006, 12:02 PM
The question here is does the counter movement of the conveyor belt create the effect of zero forward movement upon the surface of the earth, like being stuck in the mud.

-gb-

Or you could have a rope tied to the back of the plane with engines at full thrust, still wouldn't lift off. The wings might rip off the plane, though :)

Mike Teutsch
October 25th, 2006, 12:13 PM
Not mensa but:

Plane: Unless conveyor belt is creating airspeed to flow across the wing, it will not fly. What is happening in the scenario provided is that the thrust from the engines trying to get plane up to airs speed, is being offset by an equal counter force, offsetting it.


Laser question: They tie. The speed of light is a constant. Laser is at light speed. Light wave emitted from a single point in time and space will reach a distant object at the same time. Now there may be some red shift, which would allow measurement of relative speeds of the sources, but both beams should arrive at same time.


Chris my man,

There is no counter force applied to the wheels, they just roll. Thrust of the engines will move the plane. Read my full post for the explanation.

And as far the laser goes, I already answered it! :)

Mike

Chris Barcellos
October 25th, 2006, 12:41 PM
Chris my man,

There is no counter force applied to the wheels, they just roll. Thrust of the engines will move the plane. Read my full post for the explanation.

And as far the laser goes, I already answered it! :)

Mike

You must be Mensa, I'm not, but there has to be a counter force being applied to make the plane remain stationary. You have jet engines asserting force that will make the plane move forward by overcoming inertia from the plane's weight, friction from tires on ground, friction in the ball bearings, and, then you have conveyor belt running in an opposite direction overcoming the force of the get engines, to extent that it is not allowing the jet to move forward. That would have to be a counter force with respect to the planes mass being moved forward. In other words to drive that belt fast enough to offset the speed the plane would normally attain on stationary ground, energy is applied to creat a static stationary plane.....

Cole McDonald
October 25th, 2006, 12:56 PM
So then the bearings would fail? ;)

Mike Teutsch
October 25th, 2006, 01:11 PM
You must be Mensa, I'm not, but there has to be a counter force being applied to make the plane remain stationary. You have jet engines asserting force that will make the plane move forward by overcoming inertia from the plane's weight, friction from tires on ground, friction in the ball bearings, and, then you have conveyor belt running in an opposite direction overcoming the force of the get engines, to extent that it is not allowing the jet to move forward. That would have to be a counter force with respect to the planes mass being moved forward. In other words to drive that belt fast enough to offset the speed the plane would normally attain on stationary ground, energy is applied to creat a static stationary plane.....

The belt speed is inverse of the planes speed not the wheel speed. In order for the belt to move, the plane has to move and move it will.

The wheels, belt direction like I said, will either go twice as fast as normal takeoff speed or not move at all.

The belt has no real effect on the plane speed, just the wheel speed.

Mike

Chris Barcellos
October 25th, 2006, 01:27 PM
The initial post:

"If you have a large jet plane (747) sitting on a runway that was actually a giant conveyor belt (go with it). And there is also a device on the plane that communicates with the conveyor belt to tell it how fast the plane is traveling, which would then make the conveyor belt match the speed IN REVERSE.

Can the jet take off?"

Reach air speed to create lift to overcome gravity is the issue, not the speed of the ground underneath the plane. I still say in the scenario presented that every time the jets rolling speed was increased, there is a counter reaction with respect to the belt underneath, there would be virtually no change in speed of air over the wing. Therefore gravity can't be overcome, and flight not attained.

That is why planes take off into the wind. IF you take of with the wind behind you, you have to attain a higher ground speed to reach air speed, and vice versa.

Nick Jushchyshyn
October 25th, 2006, 01:36 PM
Cole summed it up perfectly:
yes, the plane could take off as it doesn't exert force against the ground to gain momentum...making the treadmill irrelevant.

Yes the plane will take off.
Thanks to the wheels, the motion of the belt does not apply force/drag on the plane, so it continues to move forward, build up speed and fly.


Here's two more .... (I was actually asked these once as part of a job interview)

A) You have nine cubes that look exactly alike. Eight have exactly the same weight, one weighs more than the others. The only tool you have to measure the weight of the cubes is a balance (like the Justice statue), but you are only permitted to use it two times.

How do you find the one cube that has a different weight from the rest?

B) You're in a room with no clock, but you can hear a bell clock in the next room that you know rings once every 15 minutes, and rings out the hour at each o'clock (rings 5 times at 5 o'clock, 6 times at 6 o'clock, etc.).

You just woke up and hear the clock ring once. What's the longest amount of time you may have to wait before being absolutely certain about what time it is? (AM/PM not a factor)

Gene Crucean
October 25th, 2006, 01:59 PM
Hehe, here we go. :D

Chris, the difference is that a plane isn't propelled by it's wheels. It's propelled by the jets which suck air in and blow it out... thus propelling the jet forward. The runway/conveyor belt has absolutely no effect. At all.

If you switched the jet with a car then yes. It wouldn't move anywhere because it IS propelled by it's wheels. Unlike a plane which has free spinning wheels.

Btw, in my initial post I didn't say anything about friction, ropes or any of the other things you guys are trying to introduce to the question. It's a set of widgets you have to problem solve with. And no you can't phone a friend either. ;)

Chris Barcellos
October 25th, 2006, 02:12 PM
Hehe, here we go. :D

Chris, the difference is that a plane isn't propelled by it's wheels. It's propelled by the jets which suck air in and blow it out... thus propelling the jet forward. The runway/conveyor belt has absolutely no effect. At all.

If you switched the jet with a car then yes. It wouldn't move anywhere because it IS propelled by it's wheels. Unlike a plane which has free spinning wheels.

Btw, in my initial post I didn't say anything about friction, ropes or any of the other things you guys are trying to introduce to the question. It's a set of widgets you have to problem solve with. And no you can't phone a friend either. ;)

I denied being mensa, but my common sense says:

Yes but initially, before flight is achieved, in order to fly, the mass of the plane must be moved through the air in order to gain speed. This is achieved by rolling against the ground to gain the air speed necessary. In this hypothetical, every time the plane is inched forward, a signal is sent to conveyor to speedup, and that pushs the plane back. The wheels are not without some friction to enable that to happen. As power is applied, it continues the forward thrust continues to match the reverse thrust of the conveyor belt. So plane is not moving with relation to surrounding air, so no lift-- no flight. I guess I need a MENSA guy to pound something into my head...

Mike Teutsch
October 25th, 2006, 02:37 PM
Chris,

Think of it this way. If that plane is sitting on the runway and all of a sudden the belt takes off at 200 mph, is the plane going to immediatly start moving at 200 mph, no. It has wheels and only a gradual increase in speed will occur, in proportion to the friction in the wheel bearings. But, the planes engines will move the plane no matter what direction the belt is going.

Mike

Robert Martens
October 25th, 2006, 02:37 PM
I was initially confused, thinking about the Bernoulli effect as it was explained to me some years ago; "The engines don't lift the plane, the wings do. If the air isn't moving over the wings, the thing won't lift off." But then I saw the explanations about a jet's propulsion, and kicked myself for being so dumb (of course the wheels don't move it forward, how could I forget a thing like that?).

To make it simpler, can't we ignore the conveyor belt? During a regular takeoff, the aircraft is being propelled down the runway with its engines. The wheels are rolling forward, and the ground is moving backward at the same speed (in a sense...it's not, really, but we can look at it that way, can't we?). There is friction between the ground and the tires, the tires and the wheels, the wheels and the axles, and even the surface of the vehicle and the air, but the thing still gets itself airborne, correct? Friction doesn't seem to matter, unless it's so strong as to prevent the craft from moving through the air, which in this case it's not.

Those engines are strong.

Gene Crucean
October 25th, 2006, 02:50 PM
-and that pushs the plane back.

Why?

Tim Le
October 25th, 2006, 03:18 PM
I have to admit when I first read this I put my pilot hat on and quickly thought it would not fly because as a pilot the first thing you think is that to generate lift you need relative airspeed over the wings and if the plane is not moving there will be no relative airspeed (assuming no wind).

But then when I put on my engineer's hat, I realized the plane's thrust is being reacted by the air, not the conveyor, so it will move forward through the air no matter how fast the conveyor is moving (and eventually take off). The key is that the wheels on a plane are free spinning so it doesn't matter what the conveyor is doing as long as the jet engines' thrust is much greater than the friction in the wheels. The plane's jet engines are pushing against the air so it will move forward relative to the air and fly.

Another way to think about this is to ask yourself, would a submarine move through a tank of water even if it was connected (through free spinning wheels) to a track underneath it that was moving in the opposite direction? The answer is yes because the submarine's propeller is pushing against the water which is independent of the track. This pushing will propel the submarine forward through the water no matter what the track is doing. Now replace the water with air and you have the same thing with the airplane.

Mike Teutsch
October 25th, 2006, 03:22 PM
-and that pushs the plane back.

Why?

What pushes the plane back? If you are talking about the belt, it is just turning the wheels.

Mike

Sharyn Ferrick
October 25th, 2006, 03:38 PM
It makes for a fun discussion

IF the pilot locked the brakes, then it would be interesting, since outside of military aircraft which can climb straight up, the thrust of the engines is not equal to the weight of the aircraft. This is why you can stand on the brakes and rev the engines and not move. IF the wheels are not locked, then as stated, they have no effect since they are there simply to reduce friction and the plane would take off.

Sharyn

Chris Barcellos
October 25th, 2006, 03:54 PM
I have to admit when I first read this I put my pilot hat on and quickly thought it would not fly because as a pilot the first thing you think is that to generate lift you need relative airspeed over the wings and if the plane is not moving there will be no relative airspeed (assuming no wind).

But then when I put on my engineer's hat, I realized the plane's thrust is being reacted by the air, not the conveyor, so it will move forward through the air no matter how fast the conveyor is moving (and eventually take off). The key is that the wheels on a plane are free spinning so it doesn't matter what the conveyor is doing as long as the jet engines' thrust is much greater than the friction in the wheels. The plane's jet engines are pushing against the air so it will move forward relative to the air and fly.

Another way to think about this is to ask yourself, would a submarine move through a tank of water even if it was connected (through free spinning wheels) to a track underneath it that was moving in the opposite direction? The answer is yes because the submarine's propeller is pushing against the water which is independent of the track. This pushing will propel the submarine forward through the water no matter what the track is doing. Now replace the water with air and you have the same thing with the airplane.


So why don't we just build conveyor belts on carriers and at airports ? And if I have my 747 sittign with lock brakes at full throttled, assuming planed doesn't rip apart, it should fly lift straight up because of the air flowing through the engines ?. I air speed over the wings it what gives lift, not air being sucked through engines. That provides the speed to overcome inertia to get the speed needed.

Greg Boston
October 25th, 2006, 03:58 PM
It makes for a fun discussion

IF the pilot locked the brakes, then it would be interesting, since outside of military aircraft which can climb straight up, the thrust of the engines is not equal to the weight of the aircraft. This is why you can stand on the brakes and rev the engines and not move. IF the wheels are not locked, then as stated, they have no effect since they are there simply to reduce friction and the plane would take off.

Sharyn

And to take that concept one further, suppose you are on a sheet of ice and stand on the brakes. The wheels won't turn, but with a lack of friction between wheels and the ice, the plane could conceivably slip forward and get enough airspeed to fly.

As to the water analogy made earlier, if you had an air boat like they use in the swamps, you could face the boat into the current then apply just enough throttle to hold your position relative to the stationary landmarks on either side of you on dry land (zero groundspeed). Or, put yourself in the water and swim. If the water current is moving against you beyond what thrust you can generate with your body, you will be swimming like mad but getting swept downstream none the less. If you were in still water and started to swim forward and someone could measure your progress and apply a current opposite to your efforts, you will swim ever faster trying to move forward, but you wil go nowhere.

Hehe, we can have a lot of fun with vector math. Just as every pilot knows how to calculate a wind correction angle to maintain a straight path over the earth. Or like when I use the trolling motor on my bass boat to face into the current and turn the prop just ehough so that I don't move relative to the landmarks (again, zero ground speed).

I kind of agree with Chris in that as thrust tries to push the aircraft forward, the conveyor belt will increase its opposite direction to keep the aircraft from moving relative to a stationary landmark (zero ground speed). Or, let's say the engines on this jet are shut off. What would happen to the aircraft if you turned on the belt?

-gb-

Chris Barcellos
October 25th, 2006, 04:00 PM
What pushes the plane back? If you are talking about the belt, it is just turning the wheels.

Mike
If you assume the perfect wheel and tire with no friction and perfect conveyor, then you might have a point, but science tells us there is no such perfect machine...

Tim Le
October 25th, 2006, 04:30 PM
So why don't we just build conveyor belts on carriers and at airports ? And if I have my 747 sittign with lock brakes at full throttled, assuming planed doesn't rip apart, it should fly lift straight up because of the air flowing through the engines ?. I air speed over the wings it what gives lift, not air being sucked through engines. That provides the speed to overcome inertia to get the speed needed.

Because the conveyor is not reducing the takeoff roll. The plane still needs to move forward through the air to generate lift. It is doing this and it is moving forward relative to the air and the earth (i.e. the airport) because the jet engines are reacting its thrust against the air. The wheels are just free spinning. They could be spinning Mach 2 and the airplane would still move forward because the thrust of the engine is way more the friction in the free spinning wheels. As long as the force trying to make the plane go forward is more than the force trying to hold it back (friction and drag), it will go forward.

If you locked the brakes and assuming the brakes were stronger than the thrust of the engine and the plane does not skid, then the plane wouldn't move at all and neither would the conveyor (the forces holding it back are now equal to or greater than the force trying to make it go forward). But that's not what the riddle says.

Chris Barcellos
October 25th, 2006, 06:40 PM
Because the conveyor is not reducing the takeoff roll. The plane still needs to move forward through the air to generate lift. It is doing this and it is moving forward relative to the air and the earth (i.e. the airport) because the jet engines are reacting its thrust against the air. The wheels are just free spinning. They could be spinning Mach 2 and the airplane would still move forward because the thrust of the engine is way more the friction in the free spinning wheels. As long as the force trying to make the plane go forward is more than the force trying to hold it back (friction and drag), it will go forward.

If you locked the brakes and assuming the brakes were stronger than the thrust of the engine and the plane does not skid, then the plane wouldn't move at all and neither would the conveyor (the forces holding it back are now equal to or greater than the force trying to make it go forward). But that's not what the riddle says.

The riddle says that the conveyor speeds up in opposite direction, every time the plane does speeds forward. I assume a balancing of forward motion against the reversing motion. The plane stay in one place relative to the air around it, therefore no air speed for lift.

A plane going down a run way, just the same as one on the conveyors is subject to many variable impeding its progess including downward force of gravity, and its affects on bearing, tire flexion, etc.

Pete Bauer
October 25th, 2006, 07:51 PM
Chris, in accordance with Newton's third law, what propels an airplane? Is it the:

a) wheels passively spinning against the ground
or
b) engine thrust against the air?

Answer is b. You don't get to add your own set of variables to a thought experiment, so considering wheel friction, etc. is a foul. Try thinking about it this way...what if instead of a giant treadmill it was wet ice and instead of wheels the plane had giant skates. (Sorry, I tried really hard to resist posting to this thread, but I obviously I succumbed. Aerodynamics 101 for non-aerodynamicist: the four primary forces acting on an airplane are thrust, drag, lift, and of course, gravity). Jet propulsion 101 for non-mechanics: all you need to know is "suck, squeeze, bang, blow."

Richard Alvarez
October 25th, 2006, 09:03 PM
Chris.

The Plane DOES react to the conveyor belt moving backwards. It reacts by rotating it's wheels TWICE AS FAST as it's forward momentum.

Another thought.

A plane is landing at 175 miles per hour. It lowers it's landing gear. The wheels are not rotating. (Or possibly even free rotating in the OPPOSITE direction of travel)

The plane touches down. The wheels do not STOP the plane. Because they are standing still. Yes, there is a great deal of friction, take a look at the end of the runway sometime.

In the scenario described, the wheels will spin TWICE AS FAST as they normally do on takeoff. That is the sum total of the effect of the conveyor belt runway on the aircraft. More wear and tear on the tires and bearings? Sure, but not enough to prevent takeoff.

And for the record, the engines do not "push against the air" the thrust within the engines pushes against the engines, escaping out the back. The total force vector in the engine translates to forward thrust. The engine pushes against the wing/fuselage. The plane moves forward. When it moves fast enough, lift is generated.

LIFT + THRUST must overcome GRAVITY + DRAG for ANYTHING to fly. We know from experience that the engine and wings of the 747 will easily overcome the drag of it's wheels spinning. THAT is the only change in the equation.

Now can I take off my P.I.C. hat and get back to editing?