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`6.02xx10^(3) g " cm"^(-3)``5xx10^(4) g " cm"^(-3)``6.02xx10^(3) g " cm"^(-3)``5xx10^(13) g " cm"^(-3)`

Answer :

CSolution :

Radius of nucleus of F atom `=5xx10^(-13) " cm"` <br> Volume of sphere `=4//3pir^(3)=4//3xx22//7(5xx10^(-13)" cm")^(3)` <br> Mass of `6.023xx10^(23)` atoms of F (or their nuclei)=19g <br> Mass a 1 atom or 1 nucleus `=19//6.023xx10^(23)g` <br> Density of matter in F nucleus `=("Mass of nucleus")/("Volume of nucleus")` <br> `=((19g)xx3xx7)/((6.023xx10^(23))xx4xx22xx(5xx10^(-13)" cm")^(3))` <br> `=6.02xx10^(13)g " cm"^(-3)`